Askold Vinogradov

en

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Askold Vinogradov

Quality:

Askold Vinogradov - Russian mathematician (1929–2005). Article “Askold Vinogradov” in English Wikipedia has 11 points for quality (as of July 1, 2025). The article contains 1 references and 2 sections.

This article has the best quality in German Wikipedia. However, this article is the most popular in English version.

Since the creation of article “Askold Vinogradov”, its content was written by 19 registered users of English Wikipedia and edited by 61 registered Wikipedia users in all languages.

The article is cited 9 times in English Wikipedia and cited 51 times in all languages.

The highest Authors Interest rank from 2001:

  • Local (English): #149925 in November 2020
  • Global: #234548 in December 2009

The highest popularity rank from 2008:

  • Local (English): #840408 in May 2010
  • Global: #1246312 in May 2010

There are 8 language versions for this article in the WikiRank database (of the considered 55 Wikipedia language editions).

The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).

The table below shows the language versions of the article with the highest quality.

Languages with the highest quality

#LanguageQuality gradeQuality score
1German (de)
Askold Iwanowitsch Winogradow
23.5281
2Russian (ru)
Виноградов, Аскольд Иванович
23.4276
3Dutch (nl)
Askold Ivanovitsj Vinogradov
20.1175
4Spanish (es)
Askold Vinográdov
14.9387
5French (fr)
Askold Ivanovitch Vinogradov
11.6528
6English (en)
Askold Vinogradov
11.0487
7Portuguese (pt)
Askold Ivanovitch Vinogradov
9.6266
8Italian (it)
Askol'd Ivanovič Vinogradov
1.0255
More...

The following table shows the most popular language versions of the article.

Most popular in all the time

The most popular language versions of the article "Askold Vinogradov" in all the time
#LanguagePopularity awardRelative popularity
1English (en)
Askold Vinogradov
34 826
2German (de)
Askold Iwanowitsch Winogradow
4 997
3Russian (ru)
Виноградов, Аскольд Иванович
4 289
4French (fr)
Askold Ivanovitch Vinogradov
1 840
5Spanish (es)
Askold Vinográdov
1 601
6Italian (it)
Askol'd Ivanovič Vinogradov
1 570
7Portuguese (pt)
Askold Ivanovitch Vinogradov
1 525
8Dutch (nl)
Askold Ivanovitsj Vinogradov
1 158
More...

The following table shows the language versions of the article with the highest popularity in the last month.

Most popular in June 2025

The most popular language versions of the article "Askold Vinogradov" in June 2025
#LanguagePopularity awardRelative popularity
1English (en)
Askold Vinogradov
90
2German (de)
Askold Iwanowitsch Winogradow
11
3Russian (ru)
Виноградов, Аскольд Иванович
11
4French (fr)
Askold Ivanovitch Vinogradov
4
5Portuguese (pt)
Askold Ivanovitch Vinogradov
4
6Spanish (es)
Askold Vinográdov
2
7Italian (it)
Askol'd Ivanovič Vinogradov
2
8Dutch (nl)
Askold Ivanovitsj Vinogradov
1
More...

The following table shows the language versions of the article with the highest Authors’ Interest.

The highest AI

Language versions of the article "Askold Vinogradov" with the highest Authors Interest (number of authors). Only registered Wikipedia users were taken into account.
#LanguageAI awardRelative AI
1English (en)
Askold Vinogradov
19
2German (de)
Askold Iwanowitsch Winogradow
12
3French (fr)
Askold Ivanovitch Vinogradov
6
4Italian (it)
Askol'd Ivanovič Vinogradov
5
5Dutch (nl)
Askold Ivanovitsj Vinogradov
5
6Portuguese (pt)
Askold Ivanovitch Vinogradov
5
7Russian (ru)
Виноградов, Аскольд Иванович
5
8Spanish (es)
Askold Vinográdov
4
More...

The following table shows the language versions of the article with the highest Authors’ Interest in the last month.

The highest AI in June 2025

Language versions of the article "Askold Vinogradov" with the highest AI in June 2025
#LanguageAI awardRelative AI
1German (de)
Askold Iwanowitsch Winogradow
0
2English (en)
Askold Vinogradov
0
3Spanish (es)
Askold Vinográdov
0
4French (fr)
Askold Ivanovitch Vinogradov
0
5Italian (it)
Askol'd Ivanovič Vinogradov
0
6Dutch (nl)
Askold Ivanovitsj Vinogradov
0
7Portuguese (pt)
Askold Ivanovitch Vinogradov
0
8Russian (ru)
Виноградов, Аскольд Иванович
0
More...

The following table shows the language versions of the article with the highest number of citations.

The highest CI

Language versions of the article "Askold Vinogradov" with the highest Citation Index (CI)
#LanguageCI awardRelative CI
1German (de)
Askold Iwanowitsch Winogradow
10
2English (en)
Askold Vinogradov
9
3French (fr)
Askold Ivanovitch Vinogradov
8
4Italian (it)
Askol'd Ivanovič Vinogradov
8
5Russian (ru)
Виноградов, Аскольд Иванович
8
6Spanish (es)
Askold Vinográdov
4
7Dutch (nl)
Askold Ivanovitsj Vinogradov
2
8Portuguese (pt)
Askold Ivanovitch Vinogradov
2
More...

Scores

Estimated value for Wikipedia:
English:
Global:
Popularity in June 2025:
English:
Global:
Popularity in all years:
English:
Global:
Authors in June 2025:
English:
Global:
Registered authors in all years:
English:
Global:
Citations:
English:
Global:

Quality measures

Interwikis

#LanguageValue
deGerman
Askold Iwanowitsch Winogradow
enEnglish
Askold Vinogradov
esSpanish
Askold Vinográdov
frFrench
Askold Ivanovitch Vinogradov
itItalian
Askol'd Ivanovič Vinogradov
nlDutch
Askold Ivanovitsj Vinogradov
ptPortuguese
Askold Ivanovitch Vinogradov
ruRussian
Виноградов, Аскольд Иванович

Popularity rank trends

Best Rank English:
#840408
05.2010
Global:
#1246312
05.2010

AI rank trends

Best Rank English:
#149925
11.2020
Global:
#234548
12.2009

Languages comparison

Important global interconnections (July 2024 – June 2025)

Cumulative results of quality and popularity of the Wikipedia article

List of Wikipedia articles in different languages (starting with the most popular):

News from 16 March 2026

On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.

In English Wikipedia the most popular articles on that day were: 98th Academy Awards, Michael B. Jordan, Paul Thomas Anderson, Jessie Buckley, Sinners (2025 film), Amy Madigan, Autumn Durald Arkapaw, Maya Rudolph, Sean Penn, Academy Awards.

About WikiRank

The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information